Question

1^2+2^2-3^2 simplify this please
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Answer 1

Answer:

$1^2+2^2-3^2=-4$

Step-by-step explanation:

$1^2+2^2-3^2$

$\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}$

$\mathrm{Calculate\:exponents}\:1^2\::\quad 1$

$=1+2^2-3^2$

$\mathrm{Calculate\:exponents}\:2^2\::\quad 4$

$=1+4-3^2$

$\mathrm{Calculate\:exponents}\:3^2\::\quad 9$

$=1+4-9$

$\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:1+4-9$

$1+4-9$

$=5-9$

$=-4$

Answer 2

Question:

Simplify:

$1^{2} + 2^{2} - 3^{3}$

Answer:

-4

Step By Step Solution:

$1^{2} + 2^{2} - 3^{2}$

$1^{2} = 1 \\ 2^{2} = 4 \\ 3^{2} = 9$

By using BODMAS rule

= 1 + 4 - 9

= 5 - 9

= -4

☆Here☆

BODMAS

B = Bracket

O = Of

D = Division

M = Multiplication

A = Addition

S = Subtraction

> It gives an order of oppressions used to solve any expression.