Question

1,2,2,3,3,3,4,4,4,4,1,1,2,2,2,2,3,3,3,3,3,3,4,4,4,4,4,4,4,4,.. Then what is the 2320 position of the number in the sequence?

Answer 1

With the above given number series, we need to find the number of 2320th position.

If we thing then it is available in the form of AP.

It is the right consideration that let us to consider a=10, c.d=10 and l=2320.

The well-known formula for this condition I = a+(n-1)d. Finally, we can get the answer as 121.