1×2+2×3+3×4+4×5+......n pado ka yog
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an=(1,2,3........n) (2,3,4,5....n)
Ap= (1+n-1)(n+1)
=n square +n
sn=sigma n square + sigma n
=n(n+1)(2n+1)/6 +n(n+)
=n(n+1)/2(2n+1/3+1)
=n(n+1)/2*2(n+2)/3
= n(n+1)(n+2)/3
Ap= (1+n-1)(n+1)
=n square +n
sn=sigma n square + sigma n
=n(n+1)(2n+1)/6 +n(n+)
=n(n+1)/2(2n+1/3+1)
=n(n+1)/2*2(n+2)/3
= n(n+1)(n+2)/3
jasmine32:
sn=sigma n square+ sigma n
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