Question

1÷√2, -2, 8÷√2 if these are in geometric progression write three more terms​

Answer 1

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Answer 2

Answer:

Answer-

Answer-( identity : (a-b)² = a²-2ab +b²)

Answer-( identity : (a-b)² = a²-2ab +b²)= {(2x - 5y)}^{2}=(2x−5y)

Answer-( identity : (a-b)² = a²-2ab +b²)= {(2x - 5y)}^{2}=(2x−5y) 2

Answer-( identity : (a-b)² = a²-2ab +b²)= {(2x - 5y)}^{2}=(2x−5y) 2

Answer-( identity : (a-b)² = a²-2ab +b²)= {(2x - 5y)}^{2}=(2x−5y) 2 = {(2x)}^{2} - 2(2x)(5y) + {(5y)}^{2}=(2x)

Answer-( identity : (a-b)² = a²-2ab +b²)= {(2x - 5y)}^{2}=(2x−5y) 2 = {(2x)}^{2} - 2(2x)(5y) + {(5y)}^{2}=(2x) 2

Answer-( identity : (a-b)² = a²-2ab +b²)= {(2x - 5y)}^{2}=(2x−5y) 2 = {(2x)}^{2} - 2(2x)(5y) + {(5y)}^{2}=(2x) 2 −2(2x)(5y)+(5y)

Answer-( identity : (a-b)² = a²-2ab +b²)= {(2x - 5y)}^{2}=(2x−5y) 2 = {(2x)}^{2} - 2(2x)(5y) + {(5y)}^{2}=(2x) 2 −2(2x)(5y)+(5y) 2

Answer-( identity : (a-b)² = a²-2ab +b²)= {(2x - 5y)}^{2}=(2x−5y) 2 = {(2x)}^{2} - 2(2x)(5y) + {(5y)}^{2}=(2x) 2 −2(2x)(5y)+(5y) 2

Answer-( identity : (a-b)² = a²-2ab +b²)= {(2x - 5y)}^{2}=(2x−5y) 2 = {(2x)}^{2} - 2(2x)(5y) + {(5y)}^{2}=(2x) 2 −2(2x)(5y)+(5y) 2 = 4 {x}^{2} - 20xy + 25 {y}^{2}=4x

Answer-( identity : (a-b)² = a²-2ab +b²)= {(2x - 5y)}^{2}=(2x−5y) 2 = {(2x)}^{2} - 2(2x)(5y) + {(5y)}^{2}=(2x) 2 −2(2x)(5y)+(5y) 2 = 4 {x}^{2} - 20xy + 25 {y}^{2}=4x 2

Answer-( identity : (a-b)² = a²-2ab +b²)= {(2x - 5y)}^{2}=(2x−5y) 2 = {(2x)}^{2} - 2(2x)(5y) + {(5y)}^{2}=(2x) 2 −2(2x)(5y)+(5y) 2 = 4 {x}^{2} - 20xy + 25 {y}^{2}=4x 2 −20xy+25y

Answer-( identity : (a-b)² = a²-2ab +b²)= {(2x - 5y)}^{2}=(2x−5y) 2 = {(2x)}^{2} - 2(2x)(5y) + {(5y)}^{2}=(2x) 2 −2(2x)(5y)+(5y) 2 = 4 {x}^{2} - 20xy + 25 {y}^{2}=4x 2 −20xy+25y 2