1/2(2x+3y)+12/7(3x-2y)=1/2
7/(2x+3y)+4/(3x-2y)=2
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Solution :
Let 1/(2x + 3y) be u and 1/(3x - 2y) be v.
Then,
➵ 1u/2 + 12v/7 = 1/2
➵ (7u + 24v)/14 = 2
➵ 7u + 24v = 7 ___(i)
➵ 7u + 4v = 2 ___(ii)
_________________________
On subtracting (ii) from (i),
➵ 20v = 5
➵ v = 1/4
Then, u = (2 - 4v)/7
➵ u = (2 - 1)/7
➵ v = 1/7
______________________________
Therefore,
➵ 2x + 3y = 7 ___(iii)
➵ 3x - 2y = 4 ___(iv)
By doing 2 × (iii) and 3 × (iv)
➵ 4x + 6y = 14
➵ 9x - 6y = 12
______________________________
On adding both we get,
➵ x = 2
and y = (7 - 2x)/3
➵ y = (7 - 4)/3
➵ y = 1
Hence value of x is 2 and y is 1.
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