Question

(1/2)^3+(1/3)^3-(5/6)^3 without qube​

Answer 1

Answer:

Step-by-step explanation:

Spelling of cube is wrong

Answer 2

if a+b+c= 0,

then a³+b³+c³= 3abc

here a+b+c is:-

1/2 + 1/3 +(-5/6) that is equal to 0

So, we can use this identity

Now,

1/2 + 1/3 +(-5/6)= 3(1/2)(1/3)(-5/6)

= -15/36 = -5/12