(1/2)^-3×(1/4^)-3×(1/5)^-3 I want qukily this ans...
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Hey there!
We observe many bases to the same exponent. so write all of the bases as a single Base by multiplication of terms
(1/2)^-3×(1/4^)-3×(1/5)^-3
=(1/2*1/4*1/5)^-3
=1/40^-3
=1^-3 / 40^-3
=1/1/1/40³
=1/1*40³/1
=40³
=64000
hope helped.!
formulae
x^m.z^m.y^m=(x.y.z)^m
a^-n= 1/a^n
We observe many bases to the same exponent. so write all of the bases as a single Base by multiplication of terms
(1/2)^-3×(1/4^)-3×(1/5)^-3
=(1/2*1/4*1/5)^-3
=1/40^-3
=1^-3 / 40^-3
=1/1/1/40³
=1/1*40³/1
=40³
=64000
hope helped.!
formulae
x^m.z^m.y^m=(x.y.z)^m
a^-n= 1/a^n
HappiestWriter012:
hope helped..
another question
Answered by
0
Hi friend!!
» (½)^-3 × (¼)^-3 × (1/5)^-3
» (2)³ × (4)³ × (5)³
» (2×4×5)³
» (40)³
» 40³
» 40×40×40
» 64000
∴The answer is 64000
» (½)^-3 × (¼)^-3 × (1/5)^-3
» (2)³ × (4)³ × (5)³
» (2×4×5)³
» (40)³
» 40³
» 40×40×40
» 64000
∴The answer is 64000
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