Question

1+2+3.....+100=?
3+7+11+.....+199=?​

Answer 1

• Gauss realized then that his final total would be 50(101) = 5050. The sequence of numbers (1, 2, 3, … , 100) is arithmetic and when we are looking for the sum of a sequence, we call it a series.

Sum of 1+3+5+7+.....+199

a=1 d=2

Finding n

th

term in A.P; a

n

=a+(n−1)d

If a

n

=199 then 199=1+(n−1)2

⇒n=100

Therefore, no. of terms =n=100

sum of 100 terms =10000

[tex][/tex]

Answer 2

Answer:

4975 first answer.

so on calculate