1+2+3+.......+100 then find out their sum?
Answers
Answered by
1
Answer:
s100 = 100/2(2a+n-1×d)=50×101=5050
Answered by
1
Answer:
The answer will be 5050.
Step-by-step explanation:
We have given;
a1 or first number = 1;
a100 or last number = 100;
total number = 100;
Hence, formula for their sum is equal to;
S = n (a1 + a100) / 2;
= 100 (1 + 100) / 2;
= (100 * 101) / 2;
= 10100 / 2;
= 5050;
That's all
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