Math, asked by prema2006bala, 9 months ago

[(1+2+3)^3]^-1 ÷ [2×3^2×(1/6)^3]^-1

Answers

Answered by msasomrat

1

Answer:

1\2592

Step-by-step explanation:

(1+2+3)^3]^-1 =1\216

[2×3^2×(1/6)^3]^-1=12

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