1+2+3+4+...+1000 = ?
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Anonymous:
500500
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Answers
Answered by
1
by sum of n nos. of ap....1000/2(1+1000)
500(1001)= 500500
500(1001)= 500500
Answered by
2
Good Morning!!!!
The given series is in A.P as the common difference is same .
I,e 2 - 1 = 1 or 4 -3 = 1
It's sum is given by this formula
N ( N + 1 ) / 2 where N = 1000
10³ ( 10³ + 1 ) / 2
500500.
Have a nice day ahead.
The given series is in A.P as the common difference is same .
I,e 2 - 1 = 1 or 4 -3 = 1
It's sum is given by this formula
N ( N + 1 ) / 2 where N = 1000
10³ ( 10³ + 1 ) / 2
500500.
Have a nice day ahead.
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