Question

1+2+3+4+................+200​

Answer 1

Answer:

sum of natural number=n(n+1)/2

=200×201/2

=20100

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Answer 2

$\large{\underline{\underline{\mathfrak{\green{\sf{Solution:-}}}}}}$.

$\large{\underline{\underline{\mathfrak{\pink{\sf{Find\:Here:-}}}}}}$.

✴$\red{\:Sum\:of\:(\:1+2+3+4+................+200)}$.

$\large{\underline{\underline{\mathfrak{\red{\sf{Explanations:-}}}}}}$.

➡Given Series in A.P.

So,

✴We Know That,

$\pink{\:Sum\:of\:n^th\:term}$.

✴$\red{\:Sn\:=\frac{n}{2}[\:{2a+(n-1)d}]}$.

➡Where,

♠n=Number of terms.

♠a= first term.

♠d=Common Different between two term.

➡Finelly , we find here.

_____________________

n=200, a=1, d=1.

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➡Keep value in Formula :-

$\implies\:Sn\:=\frac{200}{2}\:{(2*1+(200-1)*1}$.

$\implies\:Sn\:=\:100\:*\:{\:2+199}$.

$\implies\:Sn\:=\:100\:*\:201$.

$\implies\:Sn\:=\:20100$.

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