1+2+3+4+5...+100=
help plz
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The formula to calculate the sum of ‘n’ natural numbers.
S = n⁄2 (a + L)
“S” is the sum of the arithmetic sequence,
“a” as the first term,
“d” the common difference between the terms,
“n” is the total number of terms in the sequence and
“L” is the last term of the sequence.
Here a = 1
l = 100
n = 100
Sn = 100/2 (1 + 100)
= 100/2 (101)
= 50 × 101
= 5050.
Sum of 1+2+3+4……100 is 5050.
hope it helps you
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