Question

1+2+3+4+5+6..............100 times=_____

Answer 1

★ Hey mate ★


here is your answer !!!


sn = n ( a + last term ) / 2


sn = 100 ( 1 + 100 ) / 2

sn = 50 × 101


=> 5050


hence , your answer is 5050



hope it helps you dear !!!


thanks !!

Answer 2

Heya user!!!!!
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The series u have provided is in the form of an AP having it's first term as 1,last term as 100 and common difference as (2-1)=1......

So, according to formula, we have :-

Sum of n terms of an AP =n/2*(a+l)

=100/2*(1+100)

=50*101

=5050

Hope this helps!!!!!

:-)