1+2+3+4+5+6+7+8+9+10×12÷=
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Answered by
0
165hope it will help uh plz mark as brainliest Nd follow me.... :)
Mosttalented:
That is definitely wrong you can't do this question without following the BODMAS rule here I am writing the answer just see it
Answered by
1
Hi ,
Sum of first n natural numbers = n(n+1)/2
Sum of 9 natural numbers = 9(9 +1)/2
= ( 9 × 10 )/2
= 9 × 5
= 45
Now ,
1 + 2 + 3 +4+5+6+7+8+9+ 10× 12
= 45 + 10 × 12
= 45 + 120
= 165
I hope this helps you.
: )
Sum of first n natural numbers = n(n+1)/2
Sum of 9 natural numbers = 9(9 +1)/2
= ( 9 × 10 )/2
= 9 × 5
= 45
Now ,
1 + 2 + 3 +4+5+6+7+8+9+ 10× 12
= 45 + 10 × 12
= 45 + 120
= 165
I hope this helps you.
: )
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