1+2+3+4+5+6+7+8+9+10+TILL HUNDRED ,WHAT IS THE ANSWER
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♣️Hola❤️
Answer:
1+2+3+4+5+6+8+9+10.............100
By arthematic sum formula:
n/2(2a+(n-1)d)
Where a is first term
d is common difference that is 1
And nis no of terms
100/2 {2(1)+(100-1)1}
50{2+99}
50(101)
=5050 answer
❤️#sosan
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