1+2+3+4+5+6+7+8+9...99+100
Nikki57:
what to do
ok i understood
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1+2+3+4+5+6+7+8+9+..............+99+100
Cleary the above series is an A.P with first term, a=1 and common difference, d=1.
∴, S₁₀₀=100/2[2.1+(100-1)1] [∵,![S_{n}= \frac{n}{2}[2a+(n-1)d]](https://tex.z-dn.net/?f=+S_%7Bn%7D%3D+%5Cfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D++ "S_{n}= \frac{n}{2}[2a+(n-1)d]")
]
=50×(2+99)
=50×101
=5050
Cleary the above series is an A.P with first term, a=1 and common difference, d=1.
∴, S₁₀₀=100/2[2.1+(100-1)1] [∵,
=50×(2+99)
=50×101
=5050
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