1+2+3+4+5+6+7+8+9.....99
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sum of n consecutive terms = n(n+1)/2
n = 99
so, sum = 99×100/2 = 4950
n = 99
so, sum = 99×100/2 = 4950
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4878 + 1+2+3+4+5+6+7+8+9+10…………..99
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