Question

1, 2, 3, 4 5, 6 is an arithmetic progression a)find nth term b)find 30th term c)find sum of 30 terms​

Answer 1

Answer:

a)n b)30 c)465

Step-by-step explanation:

a=1 d=1

a) tn = a+(n-1)d

=1+(n-1)1

=1+n-1

=n

b)t30=a+(n-1)d

=1+(30-1)1

=1+29×1

=30

c)S30=n/2×(2a+(n-1)d)

=30/2×(2×1+(30-1)1)

=15×(2+29×1)

=15×(31)

=465