Question

1-2+3-4.......series find s81 ?

Answer 1

Answer:

(i) an = 3n + 2

Given sequence whose an = 3n + 2

To get the first five terms of given sequence, put n = 1, 2, 3, 4, 5 and we get

a1 = (3 × 1) + 2 = 3 + 2 = 5

a2 = (3 × 2) + 2 = 6 + 2 = 8

a3 = (3 × 3) + 2 = 9 + 2 = 11

a4 = (3 × 4) + 2 = 12 + 2 = 14

a5 = (3 × 5) + 2 = 15 + 2 = 17

∴ the required first five terms of the sequence whose nth term, an = 3n + 2 are 5, 8, 11, 14, 17.