Question

1/√2 +√3+√5. Rationalize x.

Answer 1

Answer:

$= \frac{1}{\sqrt{2}+\sqrt{3}+\sqrt{5} } \\\\=\frac{1}{(\sqrt{5}+\sqrt{3)} +\sqrt{2} } * \frac{(\sqrt{5}+\sqrt{3}-\sqrt{2}) }{(\sqrt{5}+\sqrt{3}-\sqrt{2})} \\\\= \frac{\sqrt{5} +\sqrt{3}-\sqrt{2} }{(\sqrt{5}+\sqrt{3)^{2} -\sqrt{2}^{2} } } \\\\= \frac{(\sqrt{5}+ \sqrt{3}- \sqrt{2} )}{6+\frac{2\sqrt{15}}{4*15} } *\frac{6-2\sqrt{15} }{6-2\sqrt{15}} \\\\= \frac{-(\sqrt{5} +\sqrt{3} -\sqrt{2} )(6-2\sqrt{5} }{24}$

Step-by-step explanation:

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Answer 2

Answer:

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