Question

1, 2, 3 = 8; 2,3,4 = 18;3,45 = 32;4,5,6=50; 5,6,7 = ?

Answer 1

Given

1,2,3=8

2,3,4=18

3,4,5=32

4,5,6=50

5,6,7=?

Take Case 1

In Which

1,2,3=8

Can We Written as

(1+2)×3-1

3×3-1=8

In second case

2,3,4=18

Can Written as

(2+3)×4-2

5×4-2=18

In Third Case

3,4,5=32

Can Written as

(3+4)×5-3

7×5-3=32

In Fourth Case

4,5,6=50

Can Written as

(4+5)×6-4

=9×6-4=50

Following This Series We Can Set A formula.

For upcoming Problems.

For Given Problem

a,b,c=z

First Term=a

Second Term=b

Third Term=c

So Formula

(First Term+Second Term)×Third Term-First Term

So Now Given Problem

5,6,7

Using Formula

(First Term+Second Term)×Third Term-First Term

(5+6)×7-5

=11×7-5

=77-5

=72

:•5,6,7=72