• 1/2-√3 find
•5/2-2√3 find
• 3/7+3√2 find
• 9/3-2√3 find
Please solve it with step by step..
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Answer:
(i) (-12)³ + (7)³+ (5)³
Let x = -12, y =7&z=5 x+y+z= -12 +7 +5=0
Here, x + y + z = 0
We know that if,
x + y + z = 0, then x² + y² + z² = 3xyz = (-12)³ + (7)³ + (5)³ = 3(-12)(7)(5) = -1260
(-12)³+ (7)³+ (5)³ = - 1260
(ii) (28)³ + (−15)³ + (-13)3³
Let x = 28, y = -15 and z = -13
x+y+z = 28-15-13-0
Here, x + y + z = 0
We know that if, x + y + z = 0, then x³ +y³ + z³ = 3xyz 3
(28) ³+ (−15)³ + (-13)³ = 3(28)(-15)(-13) = 16380
(28) ³+ (−15)³ + (-13)³ = 16380
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