Question

1/2+√3 is a root of equation x²-bx+ c=0 then find the value of b​

Answer 1

Answer:

_1+2√3_ = b.

2

Step-by-step explanation:

Given,

_1_ + √3 is a root of equation x²-bx+c=0.

2

We know that,

sum of roots = _-b_

a

_1_ + √3 = _-b_ [where a= 1]

2. a

_1+2√3_ = b. [ -b = -(-b)= +b]

2