Math, asked by prashanthlucky, 1 year ago

1+2+3+--------+n/1+3+5+------+2n-1=

Answers

Answered by sushant2505
8
(1+2+3+....+n) / (1+3+5+....+2n-1)

= (1+2+3+....+n) / (1+3+5+...2n-1) + (2+4+6+...+2n)
-(2+4+6+...+2n)

= (1+2+3+...+n) / {(1+2+3+...+2n)-2(1+2+3+....+n)}

= (n(n+1)/2) / {(2n(2n+1)/2}- 2n(n+1)/2

= (n(n+1)/2) / n(2n+1)-n(n+1)

= n(n+1)/2 / 2n²+n-n²-n

= n(n+1)/2 / n²

= (n+1)/2n

prashanthlucky: thanks
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