Question

1+2+3+...........+n/ 1+3+5+...............+2n-1​

Answer 1

Answer:

(n+1)/2n

Explanation:

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We know that,

i ) sum of first n natural numbers = n(n+1)/2

ii )Sum of first n odd numbers

= n²

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1+2+3+...........+n/ 1+3+5+...............+2n-1

= [n(n+1)/2]/n²

= (n+1)/2n

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