1+2+3+....+n = n(n+1) ÷ 2. then what would be 1+3+5+.....+31?
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As 1+2+3+...+n=n(n+1)
then ,
1+3+5...+31 = 31(31+1)÷2
=(31*32)÷2
=992÷2
= 496 (ans)
then ,
1+3+5...+31 = 31(31+1)÷2
=(31*32)÷2
=992÷2
= 496 (ans)
bikramroy76:
but the ans is given 256
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