Question

(-1/2)^5×(-1/2)^6=(-2)^x find x

Answer 1

$\textbf {\huge {ANSWER:}}$

${( \frac{ - 1}{2} )}^{5} \times {( \frac{ - 1}{2} )}^{6} = {( - 2)}^{x} \\ \\ when \: bases \: are \: same \: powers \\ add \\ \\ = > {( \frac{ - 1}{2} )}^{5 + 6} = {( - 2)}^{x} \\ \\ = > {( \frac{ - 1}{2} )}^{11} = {( - 2)}^{x} \\ \\ reciprocal \\ \\ = > { ( - 2)}^{ ( - 11)} = {( - 2)}^{x} \\ \\ powers \: only \\ \\ = > ( - 11) = x$

Answer 2

${( \frac{ - 1}{2}) }^{5} \times {( \frac{ - 1}{2}) }^{6} = {( - 2)}^{x} \\ \\ = > {( \frac{ - 1}{2}) }^{5 + 6 } = {( - 2)}^{x} \\ \\ = > {( - 2)}^{11} = {( - 2)}^{x} \\ \\ = > 11 = x$