Math, asked by rohith1070, 1 year ago

[-1/2]^5 × [-1/2]^8 = (-2)^x​

Answers

Answered by Anonymous
6

Answer:

please refer to the attachment

I hope it would help you out

thank you

Attachments:
Answered by Anonymous
13

\bigg( \dfrac{ - 1}{2}\bigg)^{5}  \:  \times  \:  \bigg( \dfrac{ - 1}{2} \bigg)^{8}  =  \: ( { - 2)}^{x}

__________ [ GIVEN ]

• We have to find the value of x.

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\rightarrow  \: \bigg( \dfrac{ - 1}{2}\bigg)^{5}  \:  \times  \:  \bigg( \dfrac{ - 1}{2} \bigg)^{8}  =  \: ( { - 2)}^{x}

 \rightarrow  \: \bigg( \dfrac{ - 1}{2}\bigg)^{5 + 8} \: =  \: ( { - 2)}^{x}

 \rightarrow  \: \bigg( \dfrac{ - 1}{2}\bigg)^{13} \: =  \: ( { - 2)}^{x}

\rightarrow\:(-2)^{-13}\:=\:({-2)}^{x}

- 2 throughout cancel

\rightarrow\:-\:13\:=\:x

\rightarrow\:x\:=\:-\:13

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x = -13

________ [ ANSWER ]

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