Question

(1,2),(-5,6) and (p,-2)are collinear,find out the value of 'p'?​

Answer 1

Step-by-step explanation:

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The value of p is -17.

Step-by-step explanation:

Since we have given that

points (1, 2), (- 5,6) and (p, - 2) are collinear,

So, Slope of (1,2) and (-5,6) would be

\dfrac{6-2}{-5-1}=\dfrac{4}{-6}=\dfrac{2}{-3}

Slope of (-5,6) and (p,-2) would be

\dfrac{-2-6}{p+5}=\dfrac{-8}{p+5}

Since the points are collinear , so their slopes should be equal to each other.

So, it becomes,

\dfrac{2}{-3}=\dfrac{-8}{p+5}\\\\2(p+5)=-3\times -8\\\\2p+10=-24\\\\2p=-24-10\\\\2p=-34\\\\p=\dfrac{-34}{2}\\\\p=-17

Hence, the value of p is -17.

Answer 2

Answer:

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