Question

1-2√5 and 1+2√5 two roots of quadratic equation are given frame the the equation​

Answer 1

Answer:

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Answer 2

Answer:

i. Let α = 10 and β = -10 ∴ α + β = 10 – 10 = 0 and α × p = 10 × -10 = -100 ∴ The required quadratic equation is x2 – (α + β)x + αβ = 0 ∴ x2 – 0x + (-100) = 0 ∴ x2 – 100 = 0 ii. Let α = 1 – 3 √5 and β = 1 + 3 √5 α + β = 1 – 3 √5 + 1 + 3 √5 = 2 and α × β = (1 – 3√5) (1 + 3 √5) = (1)2 – (3√5)2 = 1 – 45 = -44 ∴ The required quadratic equation is x2 – (α + β)x + αβ = 0 ∴ x2 – 2x – 44 = 0 iii. Let α = 0 and β = 7 ∴ α + β = 0 + 7 = 7 and α × β = 0 × 7 = 0 ∴ The required quadratic equation is x2 – (α + β)x + αβ = 0 ∴ x2 – 7x + 0 = 0 ∴ x2 – 7x = 0Read more on Sarthaks.com - https://www.sarthaks.com/844299/two-roots-of-quadratic-equations-are-given-frame-the-equation-10-and-10-ii-35-and-35-iii-and