(1÷2/9)+(1÷3whole1/5)+(1÷2whole2/3) write the result in decimal form
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0
Answer:
We have,
(1÷
9
2
)+(1÷3
5
1
)+(1÷2
3
2
)
=(1×
2
9
)+(1÷
5
16
)+(1÷
3
8
)
=(1×
2
9
)+(1×
16
5
)+(1×
8
3
)
=(
2
9
)+(
16
5
)+(
8
3
)
=
16
72+5+6
=
16
83
=5.1875
Hence,
We get 5.1875
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