Math, asked by bhatnawaz66, 4 days ago

1+2-9+8-3*2+8* is equal to​

Answers

Answered by dkaakascv52
0

Answer:

the answer is in the above attachment

Attachments:
Answered by shahegulafroz
0

Given -

1+2-9+8-3 × 2 +8

To find -

The value of 1+2-9+8-3\times2+8

Solution-

Here we have to simplify the like terms, so, we will operate the terms containing "a" with them and other constant with constant.

For simplifying we will use BODMAS,

As per BODMAS rule,

B for Bracket

O for Of

D for Divide

M for Multiply

A for Addition

S for Subtraction

So, applying the above concept

1+2-9+8-3\times2+8

Multiply 3 into 2 we get

=1+2-9+8-6+8

Add 1, 2 , 8 and 8 we get

= 3-9-6+16

when two numbers have negative sign we have to do the addition of it ans is in with (-)sign.

= 3-15+16

Add 16 and 3 we get

= 19- 15

last do subtraction of  19 and 15 we get

= 4

So,

The value of given equation is 4.

The value of 1+2-9+8-3\times2+8 is 4 .

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