Question

1/2 and 1/4 parts of two bottles are filled with milk. The bottles are then filled completely with water and the content of bottles is poured into a container. find the ratio of the milk and water in the container ​

Answer 1

Let the capacity of each bottle = 1

Total capacity of two bottles = 1+1= 2

Quantity of milk in the first bottle = $\frac{1}{2}$

Quantity of milk in the second bottle = $\frac{1}{4}$

∴Total quantity of milk in the two bottles =$\frac{1}{2} +\frac{1}{4} =\frac{3}{4}$

Hence amount of water in the two bottles = $2-\frac{3}{4}=\frac{5}{4}$

∴Required ratio of milk and water =$\frac{\frac{3}{4} }{\frac{5}{4} }$=   3/5

Answer 2

answer

3:5

step by step

$let \: the \: first \: bottle \: = \frac{x}{4}$

$x - \frac{1x}{4} = \frac{3x}{4}$

let the second bottle

$let \: \: the \: \: bottle \: = \frac{x}{2}$

$water \: in \: \: seccond \: bottle\: \\ x - \frac{x}{2} = \frac{x}{2}$

$total \: milk \: in \:both \: botlle \: = \frac{x}{4} + \frac{x}{2} = \frac{6x}{8} ( \frac{3x}{5} )$

$total \: water \: in \: both \: bottle \: = \frac{3x}{4} + \frac{x}{2} = \frac{10x}{8} ( \frac{5x}{4} )$

$ratio \: of \: water \: and \: milk \: = \frac{3x}{4} \div \frac{5x}{4} = \frac{3}{5}$

required ratio = 3:5