Question

1.
2 cubes each of volume 64 cm
are joined end to end. Find the surface area of the
resulting cuboid​

Answer 1

2 cubes each of volume:-64 cm cube

side of each cube =3√64=4 cm

area of two cubes joined together:- 6a^2 +6a^2-2a^2=10a^2

total surface area=10*4*4

=160cm sq.

Answer 2

$\huge \underline \mathbb {SOLUTION:-}$

Given:

• The Volume (V) of each cube is = 64 cm³

This implies that a³ = 64 cm³

∴ a = 4 cm

Now, the side of the cube = a = 4 cm

Also, the length and breadth of the resulting cuboid will be 4 cm each. While its height will be 8 cm.

So, the surface area of the cuboid = 2(lb + bh + lh)

= 2(8×4 + 4×4 + 4×8) cm²

= 2(32 + 16 + 32) cm²

= (2 × 80) cm2 = 160 cm²