Question

1) 2 cubes each of volume 64 cm3
are joined end to end. Find the
surface area of the resulting cuboid.

Answer 1

ANSWER

Volume of cubes = 64 cm^3

(Edge) ^3

=64

Edge=4 cm

If cubes are joined end to end, the dimension of the resulting cuboid will be 4 cm,4 cm,8 cm.

Therefore,

Surface area of cuboids =2(lb+bh+hl)

=2(16+32+32)=2×80

=160 cm^3

Answer 2

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The Volume (V) of each cube is = 64 cm^3

This implies that a^3 = 64 cm^3

∴ The side of the cube, i.e. a = 4 cm

Also, the breadth and length of the resulting cuboid will be 4 cm each while its height will be 8 cm.

So, the surface area of the cuboid (TSA) = 2(lb + bh + lh)

Now, by putting the values, we get,

= 2(8×4 + 4×4 + 4×8) cm^2

= (2 × 80) cm^2

Hence, TSA of the cuboid = 160 cm^2

Hopez it's Helpful.....:)