1
2 = DAM
1 T = MX
Q.74. A bird is flying towards north with a velocity 40 km/h and a train is moving with velocity 40km/h
towards east. What is the velocity of the bird noted by a man in the train?
(a) 40V2 km/h north-east
(b) 402 km/h south-east
(c) 4012 km/h north-west
(d) 40V2 km/h south-west
Answers
Answered by
2
Answer:
To find the relative velocity of bird w.r.t train superimpose velocity −
V
ˉ
T
on both the object. Now as a result of it the train is at rest; while the bird possesses two velocities
V
ˉ
B
toward north and −
V
ˉ
T
along west.
∣
V
ˉ
BT
=
∣
v
ˉ
B
∣
2
+∣−
V
ˉ
T
∣
2
[by formula ,θ=90
o
]
=
40
2
+40
2
=40
2
kmh
−1
north−west
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