Question

1/2 g molecule of oxygen. Find (i) mass, (ii) number of molecules, (iii) volume at STP. (iv) No. of
oxygen atoms.
Solution:
(1)
weight
n= %, mol = M
weight
= 32
=
weight of oxygen = 16 g
(i) n = 4 mol = Ñ
= Number of molecules of oxygen (N) = -A
() n = 4 mol = 22,4
= v= 11.2 litre
(iv) 1 molecule of O, contain = 2 oxygen atoms.
NA molecules of O, contain = MA x 2 = N, oxygen atoms.​

Answer 1

Answer:

oxygen atoms.

Solution:

(1)

weight

n= %, mol = M

weight

= 32

=

weight of oxygen = 16 g

(i) n = 4 mol = Ñ

= Number of molecules of oxygen (N) = -A

() n = 4 mol = 22,4

= v= 11.2 litre

(iv) 1 molecule of O, contain = 2 oxygen atoms.

NA molecules of O, contain = MA x 2 = N, oxygen atoms.​

Explanation:

Answer 2

Answer:

(1)

weight

n= %, mol = M

weight

= 32

=

weight of oxygen = 16 g

(i) n = 4 mol = Ñ

= Number of molecules of oxygen (N) = -A

() n = 4 mol = 22,4

= v= 11.2 litre

(iv) 1 molecule of O, contain = 2 oxygen atoms.

NA molecules of O, contain = MA x 2 = N, oxygen atoms



Explanation:

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