Math, asked by Sherlock5911, 5 months ago

1.2 g of FeSO4 sample (molecular weight = 152 g)
dissolved in concentrated H2SO4 completely reacts
with 50 ml of 0.01 M K2Cr2O7

Cr207^-2+6Fe^+2+ +14H^+1=>3Cr^3+ + 6Fe^3+ +7H2O

The % purity of sample is
(1) 16.33%
(2) 24.14%
(3) 17.19%
(4) 38%​

Answers

Answered by ridhiksha
1

Answer:

Percentage purity of a substance can be calculated by dividing the mass of the pure chemical by the total mass of the sample, and then multiplying this number by 100

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