1.2 gram of Mg combines with 0.8 gram of oxygen to give 2 grams of MgO. Find percentage of composition of each element in the compound . (Show the full method)
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Answer:
CHEMISTRY
MEDIUM
2Mg(s) + O
2
(g) → 2MgO(s)
If 48.6 grams of magnesium are placed in a container with 64 grams of oxygen gas and the reaction above proceeds to completion, what is the mass of MgO(s) produced?
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ANSWER
2Mg+O
2
→2MgO
The atomic masses of Mg and O are 24.3 g/mol and 16 g/mol respectively.
The molar mass of MgO=24.3+16=40.3g/mol
Number of moles is the ratio of mass to molar/atomic mass.
48.6 g of Mg corresponds to
24.3
48.6
=2 moles
64 g of O2 corresponds to
2×16
64
=2 moles
2 moles of Mg will react with 1 mole of O
2
to produce 2 moles of MgO.
Since 2 moles of O
2
are present, O
2
is excess reagent and Mg is limiting reagent.
2 moles of Mg will give 2 moles of MgO.
Mass of MgO =2×40.3=80.6g
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