Question

1÷(2-i)^2-1÷(2+i)^2 solve it with steps

Answer 1

Step-by-step explanation:

Given, 2(1+i)x2−4(2−i)x−5−3i=0

⟹x=2.(1+i)4(2−i)±16(2−i)2+4.2.(1+i).(5+3i)

=4(1+i)4(2−i)±16(4−4i−1)+8(5+3i+5i−3)

=4(1+i)4(2−i)±48−64i+16+64i

=4(1+i)4(2−i)±8 

=1+i(2−i)±2

=2(4−i)(1−i);2−i(1−i)

=23−5i;(2−i(1−i)

Hope it helps!

MARK as the BRAINIEST