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If P(E1) = 6, P(E2) = 3, P(E3) = 6 ,where E1, E2, E3, and
E4, are elementary events of a random experiment,
then P(E4) is equal to
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3
Answer:
1/3. I don't know but I tried if it will be wrong then sorry
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Answer:
1/3..
Mark me as BRAINLIEST
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