Math, asked by saharaj479, 5 hours ago

√1/2π intg(Vm^2sin^2wt) find the vakue.​

Answers

Answered by rehankhan299992
0

Answer:

= VmIm∕2 = (Vm∕√2) x ( Im∕√2). Pavg = Vrms x Irms ... (VmIm∕2) Sin(2wt) . Pavg = Pav =0∫2π(VmIm∕2) Sin (2wt) d(wt) = 0.

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