1.2 L of water leaked out from a tank with a base area of 800 square.cm . Find the the decrease in the water level in the tank.
Answers
Answer:
DK jao dp ta so su tc to spilt screen shot of the name of the
Step-by-step explanation:
foggy in the world of any three of the name of the world of any three
Answer:
Area of the hole of the water tank-2mm² Height of filled waterh=80
cm
Area of the cross-section of the tanksA = 0.4m²
Feedback
三
Acceleration due to gravity g= 9.8ms 2 = 10ms-2 Pressure at the open surface and at the hole is equal to the atmospheric pressure.
(a) Velocity of water
v = √2gh = √2 × 10 × 0.80 = 4m/s
Velocity of water when the tank is half-filled and his 40cm 80 2 √2gh = √2 × 10 × 0.40 = √8m/s =
Volume - Ah = Avdt =
= AX √2ghdt
= (2mm²) √2ghdt
Feedback
Σ
Volume of the tank= Ah = V
(say) dv dh → = A dt dt
dh dt a₁V₁ A
⇒ 2 × 10 √2gh = 0.4 -6 dh dt
⇒dh = 5 x 10-6√/2ghdt
(d). dh = 5 x 10-6√2ghdt
dh √2gh = 5 x 10-6dt
On integrating we get 5×10 / dt = v28 cho ăn 10-6 1 0.4 dh 0.8
⇒5 x 106 x t = 1 √28 2h² 0.4 0.8
1 28 ⇒ t = V × 2 [(0.4)² - (0.8) ³] × 5 × 10¹5 X 1
⇒ t = 1 4.47 x 2 x 2 3.16 1 5 x 10-6 X X ¹ h 3600
= 6.51h .. t = 6.51
Thus, the time required to leak half of the water out is 6.51hrs.
Step-by-step explanation: