Question

1/2 log 9 - 3 log 4 + 3 log 2

Answer 1

Answer:

$\frac{1}{2} log(9) - 3 log(4) + 3 log(2) \\ = \frac{1}{2} log( {3}^{2} ) - 3( log(4) + log(2) ) \\ = log(3) - 3( log(4 \times 2) \\ = log(3) - 3( log( {2}^{3} ) \\ = log(3) - 9 log(2) \\ = log(3) - log( {2}^{9} ) \\ = log( \frac{3}{ {2}^{9} } ) \\ = log( \frac{3}{512} )$