Question

1/2 [m(arcAC) + m(arcDB)] = ?​

Answer 1

$solution$

=AB2+CA2 → BC=√62+62

BC-6√2 cm ...

m(arc RS) + m(arc QS) + m(arc QR) = 360°

(Measure of a complete circle is ... ZABE =

12[m(arc AE) + m(arc DC

Answer 2

Concept Introduction:-

Curve segments, such as a circle's circumference, are called arcs.

Given Information:-

We have been given that $1/2 [m(arcAC) + m(arcDB)]$

To Find:-

We have to find that the value of  $1/2 [m(arcAC) + m(arcDB)]$

Solution:-

According to the problem

$m$∠$AC=CE$∠$AEC$

$m$∠$DB=BE$∠$BED$

$m$∠$AC+m$∠$DB=2r$∠$AEC$

∴$\frac{1}{2}[m$∠$AC+m$∠$DB=r$∠$AEC$.

Final Answer:-

The value of  $1/2 [m(arcAC) + m(arcDB)]$ is ∠$AEC$, so, option $1$ is correct.