Question

1.2 Molar,250 ml h2so4 solution is diluted by 500ml water. Find the Normality of solution.​

Answer 1

Answer:

Explanation:N1V1=N2V2

N1=1.2×2=2.4

V1=250ml

V2=500ml

Puting these values in eq we get

2.4×250=N2×500

N2=1.2

I am not sure

Answer 2

The normality of diluted solution is 1.2 N

Explanation:

To calculate the normality of the solution, we use the equation:

$N=n\times M$

where,

N = normality of solution

n = basicity for acids = 2 (for sulfuric acid)

M = molarity = 1.2 M

Putting values in above equation, we get:

$N=2\times 1.2=2.4N$

To calculate the concentration of diluted solution, we use the equation:

$N_1V_1=N_2V_2$

where,

$N_1\text{ and }V_1$ are the normality and volume of the concentrated sulfuric acid solution

$N_2\text{ and }V_2$ are the normality and volume of diluted sulfuric acid solution

We are given:

$N_1=2.4N\\V_1=250mL\\N_2=?N\\V_2=500mL$

Putting values in above equation, we get:

$2.4\times 250=N_2\times 500\\\\N_2=\frac{2.4\times 250}{500}=1.2N$

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