Question

(-1,2 ),r=5 find the equation of circle with centre c and radius r where


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Answer 1

Step-by-step explanation:

standard equation of circle is

(x-a)²+(y-b)²=r²

where (a,b)=(-1,2) r=5

(x-(-1))²+(y-2)²=5²

x²+y²+2x-4y+5=25

therefore,

equation of circle is

x²+y²+2x-4y-20=0

Answer 2

The required equation of the circle is x² + y² + 2x - 2y = 20  

Given:

The coordinate points of center c (-1, 2) and r = 5

To find:

Find the equation of the circle with center c and radius r where

Solution:

Formula used:

Standard equation of a circle is (x - a)²+(y - b)² = r²

Where (a,b) is the coordinate of centers and r is the radius

From the data,

Center of the circle (a, b) = (-1, 2)

And the radius of the circle r = 5

Using the formula,

Equation of the circle is

=>  (x - (-1))²+(y - 2)² = (5)²

=>  (x + 1)²+(y - 2)² = 25

=>  x² + 1 + 2x + y² + 4 - 2y = 25

=>  x² + y² + 2x - 2y = 20

Therefore,

The required equation of the circle is x² + y² + 2x - 2y = 20

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