1/2-root3-1/root3+root2+5/3-root2
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rationalise the denominator
1/2-√3×2+√3/2+√3
2+√3/
(2)^2-(√3)^2
2+√3/
4-3
2+√3-√3-√2+3+√2
all will be canceled
2 + 3 is left
so the answer is 5
1/2-√3×2+√3/2+√3
2+√3/
(2)^2-(√3)^2
2+√3/
4-3
2+√3-√3-√2+3+√2
all will be canceled
2 + 3 is left
so the answer is 5
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