Question

1/2 sin²30°. cos²45° + 4tan²30°=....​

Answer 1

Answer:

We know that, Sin30°=(1/2), Cos45°=(1/√2), Sin90°=1, Cos90°=0, Cos0°=1 & tan30°=(1/√3), putting these values in the given expression, we get :-

sin230∘cos245∘+4tan230∘+12sin290∘−2cos290∘+124cos20∘sin230∘cos245∘+4tan230∘+12sin290∘−2cos2⁡90∘+124cos20∘

=(12)2×(12√)2+4(13√)2+12×(1)2−2×(0)2+124(1)2=(12)2×(12)2+4(13)2+12×(1)2−2×(0)2+124(1)2

=14×12+4×13+12×1−2×0+124×1=14×12+4×13+12×1−2×0+124×1

=